What is the hybridization of NH2 BCl2

You must first draw the Lewis structure for .

According to VSEPR theory, we can use the steric number to determine the hybridization of an atom.

= number of lone pairs + number of atoms directly attached to the atom.

  • corresponds to hybridization.
  • corresponds to hybridization.

We see that the atom has . It has no lone pairs, but it is attached to two other atoms.

It has hybridization.

Each atom has . It has 2 lone pairs and is attached to 1 atom.

Just as the carbon atom hybridized to form the best bonds, so do the oxygen atoms.

The valence electron configuration of is .

To accommodate the two lone pairs and the bonding pair, it will also form three equivalent hybrid orbitals.

Two of the orbitals contain lone pairs, while the remaining orbital and the unhybridized orbital have one electron each.

We can see this arrangement in the bond of formaldehyde, which is equivalent to the right-hand side of the molecule.


(from www.slideshare.net)

There is a similar arrangement on the left side of the molecule, but the bond is horizontal rather than vertical.

Here is a video about the hybridization of carbon dioxide.